from datetime import datetime, date, time
year = 2017
month = 8
day = 29
hour =18
minute = 4
second = 15
dt = datetime(year, month, day, hour, minute, second)
dt.hour, dt.minute, dt.second
(18, 4, 15)
Extract the equivalent date object:
dt.date()
datetime.date(2017, 8, 29)
Extract the equivalent time object:
dt.time()
datetime.time(18, 4, 15)
When aggregating or grouping time series data, it is sometimes useful to replace fields of a series of datetimes such as zeroing out the minute and second fields:
dt.replace(minute=0, second=0)
datetime.datetime(2017, 8, 29, 18, 0)
Format a datetime string:
dt.strftime('%m/%d/%Y %H:%M')
'08/29/2017 18:04'
Convert a string into a datetime object:
datetime.strptime('20170829', '%Y%m%d')
datetime.datetime(2017, 8, 29, 0, 0)
Get the current datetime:
dt_now = datetime.now()
Subtract two datetime fields to create a timedelta:
delta = dt_now - dt
delta
datetime.timedelta(0, 8, 836993)
Add a datetime and a timedelta to get a new datetime:
dt + delta
datetime.datetime(2017, 8, 29, 18, 4, 23, 836993)