from __future__ import division, print_function
Write a function called invertBool(l)
that takes in a list of lists called l
, and returns a list of lists that represents all the booleans in the matrix, inverted.
For example:
invertBool(
[[True, False, True], [False, True, True], [False, False, False]])
=>
[[False, True, False], [True, False, False], [True, True, True]]
# write code here
Run the following cell to test your invertBool(l)
function.
def test():
lsts = [[[True, False, True, True],
[False, False, False, True],
[True, True, True, True],
[False, True, False, True]],
[[False, True, False],
[True, True, True],
[False, False, False]]]
ans = [[[False, True, False, False],
[True, True, True, False],
[False, False, False, False],
[True, False, True, False]],
[[True, False, True],
[False, False, False],
[True, True, True]]]
for i in range(2):
if invertBool(lsts[i]) != ans[i]:
return "Test Failed :'("
return "All Tests Passed!"
test()
'All Tests Passed!'
Write a function called diagProd(l)
that takes in a list of integer or float lists where each nested list are the same length, and returns the product of a matrix's diagonal. You may assume the list is non-empty.
For example:
diagProd(
[[12, 5, 3], [2, 1, 3], [35, 23, 2]]
)
will return 24
.
# Write your function here
Run the following cell to test your diagProd(l)
function.
def test():
lst = [
[[12, 5, 3],
[2, 1, 3],
[35, 23, 2]],
[[54, 345, 23, 25],
[135, 43, 3, 5],
[75, 46, 63, 15],
[16, 10, 9, 2]],
[[1]],
[[2, 4],
[4, 2]]
]
ans = [24,292572, 1, 4]
for i in range(2):
if diagProd(lst[i]) != ans[i]:
return "Test Failed :'("
return "All Tests Passed!"
test()
'All Tests Passed!'
Write a function called symmetric(l)
that takes in a list of integer lists called l
, and returns a boolean on whether or not the matrix is symmetric. Recall that a matrix is symmetric if and only if when the ith columm becomes the ith row, it is still the same matrix.
Hint: You can do this without looking at the elements more than once.
For example:
symmetric(
[[12, 5, 3], [2, 1, 3], [35, 23, 2]] )
will return False
.
symmetric(
[[1, 4, 5], [4, 2, 6], [5, 6, 3]] )
will return True
.
# Write your code here
Run the following cell to test your symmetric(l)
function.
def test():
lst = [[[12, 5, 3],
[2, 1, 3],
[35, 23, 2]],
[[1, 4, 5],
[4, 2, 6],
[5, 6, 3]],
[[2, 4],
[4, 2]],
[[54, 345, 23, 25],
[135, 43, 3, 5],
[75, 46, 63, 15],
[16, 10, 9, 2]]
]
ans = [False, True, True, False]
for i in range(4):
if symmetric(lst[i]) != ans[i]:
return f'Test Case #{i +1} Failed'
return "All Test Cases Passed!"
test()
'All Test Cases Passed!'
Write the function advancedCheckered(x)
that takes in an integer s
and prints a s
by s
checkerboard that has hashtags starting on even lines, and has percent signs starting on the odd lines, and they alternate during the line.
For example:
advancedCheckered(4) →
#%#%
%#%#
#%#%
%#%#
# Write code here
An image is usually represented as a 2D array, but let's say we only have access to a 1D array. Is there a way that we can represent a 2D array using a 1D array? Here's a picture that describes how we can store an image as a 1D array.
Write a function called getPixel(lst, h, w, i, j)
where lst
is a 1D array, h
is the height of the image, w
is the width of image, i
is the row that the pixel is on, and j
is the column that the pixel is on. Then, this function will return the value that the pixel holds.
Write a function called 1Dto2D
that takes in a list of integer pixels lst
, height h
, and width w
and returns the 2D array representation of the image.
For example:
1Dto2D([34, 234, 23, 255, 98, 23, 155, 87], 2, 4) →
[[34, 234, 23, 255],
[98, 23, 155, 87]]