1 + 3
%%html
Cette cellule contient du HTML !
Remarquez la clef magique %%html
.
a = 1
a
type(a)
a = "toto"
a
type(a)
a + 1
a.upper()
b = a.upper()
b
a
a = 1
b = 2
a =
2
a = "toto"
a == 'toto'
a[1]
type(a[1])
a = "tot
o"
a = """
Mignonne, allons voir si la rose
Qui ce matin avoit desclose
Sa robe de pourpre au Soleil,
"""
a
print a
"La reponse est %d" % 42
"La %s est %d" % ("question", 24)
a = 1
a == 1.0
a = 1000000
a * a * a * a * a * a
a**6
True == (not False)
True and False
True or False
a = ["a", "b", "c"]
a[1]
len(a)
a[2] = "d"
a
a[3]
a[3] = "e"
a.append("e")
a
" ~~=> ".join(a)
a = { "couleur": "rouge", "forme": "rond"}
a
len(a)
a["couleur"]
a["taille"] = "grand"
a
if 1 + 1 == 2 and 1 - 1 > 0:
a = 10
print "faux"
elif 3 + 4 == 7:
a = 3
print "yes"
else:
a = 4
print "no"
a
i = 0
while i < 10:
print i
i += 1
a = ["a", "b", "c"]
for x in a:
print x
range(10)
for i in range(10):
print i
def ma_fonction(x, y):
c = 2*x
return c + y
ma_fonction(2, 3)
def fct(x, y=3, z=10):
return x + y + z
fct(2), fct(2, 4), fct(2, 4, 1), fct(2, z=3)
import numpy
from pylab import imshow, show
from timeit import default_timer as timer
%pylab inline
def mandel(x, y, max_iters):
"""
Given the real and imaginary parts of a complex number,
determine if it is a candidate for membership in the Mandelbrot
set given a fixed number of iterations.
"""
c = complex(x, y)
z = 0.0j
for i in range(max_iters):
z = z*z + c
if (z.real*z.real + z.imag*z.imag) >= 4:
return i
return max_iters
def create_fractal(min_x, max_x, min_y, max_y, image, iters):
height = image.shape[0]
width = image.shape[1]
pixel_size_x = (max_x - min_x) / width
pixel_size_y = (max_y - min_y) / height
for x in range(width):
real = min_x + x * pixel_size_x
for y in range(height):
imag = min_y + y * pixel_size_y
color = mandel(real, imag, iters)
image[y, x] = color
image = numpy.zeros((1024, 1536), dtype = numpy.uint8)
start = timer()
create_fractal(-2.0, 1.0, -1.0, 1.0, image, 20)
dt = timer() - start
print "Mandelbrot created in %f s" % dt
imshow(image)
show()